Hello FP.
I have _had_ to move on - no choice - found another engine and am fitting it. Mistake has cost me about £300 in parts and another second hand engine. As you say learn and at least check with the 'normal' twist method next time as a safety check and do not allow myself to go slacker than the 45 degree twist criterion.
However good news: I have I think found final definitive answers now with some research on the internet.
Here is the Rosetta Stone of different units and data on cambelt tension measurement:-
www.autodata-online.com/uk/tbinfo.pdf
This has on page 9 of 11 a table of eight tension measurement devices and their units used. It therefore gives comparison of the units including SEEM units. It does not give a comparison of resonant frequency however. That has to be calculated; as follows:
Looking at the table: Lo and behold we have two SEEMS devices mentioned; a SEEM C.Tronic G2 105.5 and a SEEM C.Tronic 87 (curiously, and oddly, measuring slightly differently for a given tension value of force in Newtons for the first instrument which is a Burroughs BT33-73F / BT33-86J).
Here is the table comparison for the Burroughs (as above) and the SEEM C.Tronic G2 105.5:-
150 Newtons = 33 SEEM units
200 N = 40 SEEM
250 N = 47 SEEM
300 N = 53 SEEM
350 N = 61 SEEM
400 N = 67 SEEM
450 N = 72 SEEM
500 N = 78 SEEM
You will note the difference between SEEM units for each 50 Newtons increase is non-linear. These SEEM units are very strange indeed. Clearly they are completely arbitrary to the device.
So the next problem was to establish what the 41 SEEMs recommended in Haynes for the DW8 engine is in Hz. We proceed as follows:
Measuring the belt total length it was 1338mm = 1,338Metres. (It is marked at 1.4Metres, but we really need the mid-point of the belt section so I used the measured value as above). Measuring the span across the two pulleys (camshaft and diesel pump) which is what vibrates, was 240mm = 0.24Metres. Measuring the total mass of the belt was found to be 169 Grams for the new belt; and 166 Grams for the old belt. 169 Grams was used which = 0.169Kg. Hence the mass per unit length = m = 0.168 / 1.4 which = 0.12 Kg per Metre. We now have all the data for using the Clavis formula for frequency of a span of belt which is:-
Tension in Newtons = T = 4 m L^2 F^2
or, F = square root of { T / ( 4 m L^2 ) }
where F= frequency in Hz and L = span length in Metres. m = mass per unit length
As 40 SEEM units = 200 Newtons,
putting 200 for T (Tension) and finding F in the formula, Frequency = 85.1Hz
putting 250 Newtons for T, Frequency = 95Hz
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Conversely; as I set the belt at 41 Hz I can now find the tension in the belt which I set it to. Solving for 41 Hz gives a belt tension of 46.5 Newtons. So there was tension in the belt but it was only a quarter of what it should have been.
I measured the cambelt Hz for the replacement DW8 engine and it was found to be 68 Hz, that solves for a belt Tension of 128 Newtons; which is 0.68 (nearly three quarters) of the 200 Newtons it should be. I shall tighten it to 85Hz = 200 Newtons.
I think I am now satisfied I have explored this subject to its conclusion. Which is: yes I was in error. I paid the penalty. No the belt was not totally slack it was a quarter slack.
I also think the piston to cyl head gap distance was probably marginal and contributed to the problem however, with the absolute minimum head gasket thickness which I allowed for, and should have chosen one value thickness more.
One lives and learns.
Thank you all who have helped me towards a better understanding of what it is all about.
Douglas Denny.
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